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```On Sunday 6th FEB 2022 I addressed this question in my D.E. Shaw online test for FTE. I found this question interesting so I want the community to solve it too.

Ques) In order to reduce the water bill in hissociety, You decided to switch to a new water supply system.

You are given an array TargetWaterSupply of size N denoting the target monthly water consumption in liters of N houses.

At the start of the month, let' say that all the houses have 0 liters of water present. You came accross a unique water supply system where he can do 2 operations:

Increase the quantity of a specific house by 1 liter.

Double the quantity of all houses.

To avoid wastage, you want the exact amount of water to be generated as required by the houses. To minimize the bill he needs to achieve this task in minimum no. of operations. Write a code to achieve that.

Constrains:

0<=N<=4*10^5.

0<= TargetWaterSupply[i] <=10^9.

Example 1:

Input

TargetWaterSupply=[1,5,4,8]

Output

8

Explanation:

operation 1: [0,0,0,1] operation 2: [0,0,0,2] operation 3: [0,0,1,2] operation 4: [0,1,1,2] operation 5: [0,2,2,4] operation 6: [0,4,4,8] operation 7: [0,5,4,8] operation 8: [1,5,4,8]

Example 2:

Input

TargetWaterSupply=[]

Output

0

Example 3:

Input

TargetWaterSupply=[0]

Output

0

Solution Apprroach:

int MinOperations(vector<int>& TargetWaterSupply) {
sort(TargetWaterSupply.begin() , TargetWaterSupply.end() );
int ans=0,maxDouble=0;
for(int ele : TargetWaterSupply){
int inc=0,multiply=0;
while(ele>0){
if(ele%2==0){
multiply++;
ele/=2;
}
else {
inc++;
ele--;
}
}
if(multiply>maxDouble){
maxDouble=multiply;
}
else multiply=0;
ans+=inc+multiply;
}
return ans;
}```
by Expert (113,040 points)