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Link to my solution code :

The basic idea , is that a self destructing string should have equal number of ones and zeroes  , so check if the given input string has even length , if yes, then , find the number of zeroes that you need to convert to "1" (or vice-versa), to get a string which has 'x' zeroes and 'x' ones , where x = n/2(length of string :n) .

Hope it helps!
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